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how to divide a sin-wave by 2 with a simple way?

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butterfish

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sin-wave divider??

Hi, dear all,
My question is how to divide a sin-wave by 2 with a simple way?

There is a 128MHz sin-wave (0~0.6v, from crystal oscillator) input, and I need a 64MHz output (output can be sin-wave or square wave, 0~0.6v, differential output would be the best).
Usually we shift1 128MHz sin-wave to square wave, and divide it by 2 with a DFF, then shift2 the square wave to 0~0.6v. but the two level shift means the worse phase noise.
For better phase noise, how to divide the 128MHz sin-wave without the two level shift?

Thanks in advance!
 

Use a PLL. No.. not divide by 2 :), but multiply by 2, and you will get the 64 MHz signal. This app note will be of some help : **broken link removed**

Hope this helps
 

If you are using 128MHz crystal and you want 64MHz, why don't you use simply 64 MHz crystal to make your life easy.
 

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