Manoj_N
Newbie
I wanted to design an X-Band 1:2 Microstrip T-junction power divider using ADS but I couldn't achieve the desired condition that is S(2,1) = S(3,1) = 0. Can someone help to solve this problem?
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This is not possible with a passive divider. Best case for a lossless divider is S21=S31=-3dBI couldn't achieve the desired condition that is S(2,1) = S(3,1) = 0.
My return loss should be less -30dB for optimum performance. Same for port 2 and 3Hi!
Why do you need that condition? What is your input? port 1?
Regards
how to is -3dB? Is there a way to calculate it?This is not possible with a passive divider. Best case for a lossless divider is S21=S31=-3dB
Check the attachment. I designed the schematic.Hi!
Why do you need that condition? What is your input? port 1?
Regards
This is simple: in an ideal lossless case, each output gets half the power (-3dB).how to is -3dB? Is there a way to calculate it?
in a couple such as this, adding a 100 ohm chip resitor across the two outputs near the end of the two quarter wave lines WILL make it behave happier in your circuit. that is because if there are different load conditions for the two outputs, the resistor will absorb some of that mismatch power.Check the attachment. I designed the schematic.
View attachment 185964