klp
Newbie level 6
Hi, I have designed this mixer:
the open stubes C and D calculated for lenght of quarter lambda for LO and RF frequencies.
I would like to ask, why does the open stubs (C,D) improves the conversion loss?
conversion loss=Pif[output power]-Prf[input power]
I mean the Prf does not changes since it is the RF input power (let assume -15dBm).
so why does the conversion loss improves because of C,D open stubs?
Is Pif increased because of the stubs? if yes, why?
thanks alot.
the open stubes C and D calculated for lenght of quarter lambda for LO and RF frequencies.
I would like to ask, why does the open stubs (C,D) improves the conversion loss?
conversion loss=Pif[output power]-Prf[input power]
I mean the Prf does not changes since it is the RF input power (let assume -15dBm).
so why does the conversion loss improves because of C,D open stubs?
Is Pif increased because of the stubs? if yes, why?
thanks alot.