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It actually is, the table is correct.First row has QA, QB snd Qc = 0, yielding the D, S, R, J and K you have listed. But the three Q's after the clock will not be 0, 0, 0.
According to schematic symbol, the flip flops are negative edge triggered, state is advancing on 1->0 transition of the clock input.Where the arrows are only when we get clock is 1