jakejake
Newbie level 4
Hi, my question is: does synopsys dft compiler simulate SE=1 when performing dft_drc? When doing dft drc debugging, I see SE=X in design vision. Is this supposed to happen? Thanks.
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Hi, my question is: does synopsys dft compiler simulate SE=1 when performing dft_drc? When doing dft drc debugging, I see SE=X in design vision. Is this supposed to happen? Thanks.