Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

CDF of two exponential random variables

Status
Not open for further replies.

aliazmat

Banned
Joined
Mar 14, 2008
Messages
76
Helped
5
Reputation
10
Reaction score
2
Trophy points
1,288
Activity points
0
I want to find out the cdf

Fx(x)=Pr(X ≤ k)

where "X" is a Rayleigh distribution and "k" is some other Rayleigh distribution with may be different mean and variance.

How can I find it out, somebody help me please.
 

If distributions are the same, then Pr (x<= y ) is 1/2.

If distributions are different, then Pr (..) = ∫ ( f(x) * f(y) * (sign(y-x) +1)/2 ) dx dy
 

Thanks for your reply , it would be nice if you could elaborate the solution a little.
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top