tajiknomi
Member level 4
I have an OpAmp which states that its Input Offset Voltage is 2mV typical but I want to practically calculate the actual offset it will have at the room temperature. So I have connected the circuit in the following manner on the breadboard.
The Ouput voltage i got is 4.4mV, so does this means that the input offset in practice at the current temperature is (Output Offset / Gain) i.e 4.4mV/2V2 => 2mv ?
P.S : I also measure the output of 72mV when i connected the Inverting and non-Inverting inputs directly to ground. When i left the input both open(floating), the output comes out to be 50~54mV
The Ouput voltage i got is 4.4mV, so does this means that the input offset in practice at the current temperature is (Output Offset / Gain) i.e 4.4mV/2V2 => 2mv ?
P.S : I also measure the output of 72mV when i connected the Inverting and non-Inverting inputs directly to ground. When i left the input both open(floating), the output comes out to be 50~54mV
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