liusupeng
Advanced Member level 4
for the simple flash ADC, the voltage reference for each comparator is generated by injecting a current into a series of resistors. suppose one LSB is R*I. The bottom resistor should be of value R or R/2?
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In the one bit case, the output thermal code will be 00, 01, 11. How should i translate this to binary code of 0 and 1? 00 correspond to 0? bot 01 and 11 correspon to 1?It is R/2 AFAIK.
Lets suppose its a one bit ADC... you now need two take off points from the resistor ladder.
Recall that the top of the resistor ladder is connected to Vcc and bottom to Gnd.
So for two take off points, you effectively need three resistors, say A, B and C so that you get two take off points, ie between A-B and the other between B-C.
Now since the overall quantization is just around two levels in this case, it is customary to have sum of resistors in ladder = 2R.
Hence for symmetry the top and bottom resistors will be R/2, while central one is R.
You can extend the same logic for 2bit, 4 bit etc...
for 2 bit:R/2,R,R,R,R/2
for 4 bit:R/2,R,R,R,R,R,R,R,R/2
Hope it helps...
could you please rephrase your question?
I don't understand your question..
in one bit caseutput will be either 0 or 1.... NOT 00, 01, 11
in two bit case: it will be 00,01,10,11