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I think a current sinkWhere does this node View attachment 126197 go to? Is it a resistor or a current sink to GND ?
Sure.all the transistors should be in saturation, is it true?
Sorry, I neither have the time nor your simulator & simulation models. Just can give you some advice. First isolate A (m8 .. m13) and try and get its gain a little bit >1 : if it's too much over 1, it will oscillate.Do you have any idea help me to do correct simulation?
Sure.
Sorry, I neither have the time nor your simulator & simulation models. Just can give you some advice. First isolate A (m8 .. m13) and try and get its gain a little bit >1 : if it's too much over 1, it will oscillate.
Play with the W/L ratios of the transistors. Then reconnect it and simulate the whole amp.
4 notes:
1. You didn't connect the transistor substrates. Is this done automatically by your tool?
2. You can never expect to measure a negative conductance at Vo - and you ruin the amp's gain as long as you have a 50Ω load connected to it.
The aim of this amplifier is to achieve a huge output resistance (at node Vo) with the help of this negative conductance circuit part (the red box above).
Means:
3. you can only achieve and measure a negative conductance at the red box part - not at the whole amplifier.
4. you must not load the output Vo at all - this is the precondition to achieve high gain with a single stage amp.
Good! It seems your terminator is just a virtual 50Ω resistance, not a real one. So what is it for?it seems that 50ohm term dont load the desired circuit, and after simulation Z(1,1) and Y(1,1) are input resistance and conductance of two 400ohm resistors without 50ohm term
Did you trim the circuit for a gain of a little bit more than 1 ?it is my final simulation setup and the waveforms of nodes that showed in picture, ofcourse it dont get me negative conductance yet :thumbsdown:
I dont know what is it for, but it is the proposed technique (simulation setup) for measure the input impedance of a circuit by the ADS simulator, and should be placed a 50ohm term at the node that we want to measure input impedanceGood! It seems your terminator is just a virtual 50Ω resistance, not a real one. So what is it for?
Did you trim the circuit for a gain of a little bit more than 1 ?
BTW: You can measure its conductance only at node Vin.
Ok, probably an ADS specialty (I don't know this simulator).I dont know what is it for, but it is the proposed technique (simulation setup) for measure the input impedance of a circuit by the ADS simulator, and should be placed a 50ohm term at the node that we want to measure input impedance
May be this gain is too high. Try to get it to 1.0 ≤ gain ≤ 1.05 .Yes, I try to design the circuit for a gain little more than 1, ofcourse the waveforms that I had attached showed the Vin is 200mV peak to peak and Vo3 is 238mV,
Yes, the source follower is needed for low output impedance, because it doesn't connect to a gate, but to a node with lower impedance.before common drain stage I achieve more gain (near 2 or 2.5) , can I delete the common drain stage or it is needed??
Ok. May be you cannot measure a negative conductance directly. Test the conductance difference of the single stage amplifier without and with the red box circuit. It should be lower (impedance higher) when the negative conductance circuit (NCC) is connected to it (Vin to Vo).Yes, I had measured the conductance at Vin, and 50ohm term connected to this node
Hi dear eriklOk, probably an ADS specialty (I don't know this simulator).
May be this gain is too high. Try to get it to 1.0 ≤ gain ≤ 1.05 .
Yes, the source follower is needed for low output impedance, because it doesn't connect to a gate, but to a node with lower impedance.
Ok. May be you cannot measure a negative conductance directly. Test the conductance difference of the single stage amplifier without and with the red box circuit. It should be lower (impedance higher) when the negative conductance circuit (NCC) is connected to it (Vin to Vo).
Take care that you don't change the DC node voltage by the connection, because neither the DC output impedance of the one-stage-OTA nor the Vin impedance of the red box (NCC) is infinite. That means Vo and Vin should be the same before and after the connection.