jasmin_123
Full Member level 3
- Joined
- Feb 1, 2007
- Messages
- 182
- Helped
- 8
- Reputation
- 16
- Reaction score
- 1
- Trophy points
- 1,298
- Location
- Rio de Janeiro
- Activity points
- 2,545
In the GIC below one can change the OpAmps polarities and also do some other modifications without changing the impedance Z=(Z1*Z3*Z5)/(Z2*Z4).
So, why the conventional circuit is always as shown in the diagram and not a different one?
So, why the conventional circuit is always as shown in the diagram and not a different one?