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Apply input waveforms of various voltages and shapes?
See what the output waveform looks like?
Likewise try setting different Ampere levels in the current sources.
Eventually you can expand the range so that you can apply rail-to-rail input levels. It probably will require making many adjustments of volt levels, current levels. I suppose the aim is to avoid clipping of the output.
Thank you BradtheRad. but I want to draw the small signal equivalent circuit for the complementary circuit. I am not looking to the range or same like that, just the equivalent circuit.
Thank you BradtheRad. but I want to draw the small signal equivalent circuit for the complementary circuit. I am not looking to the range or same like that, just the equivalent circuit.
I guess such an equivalent circuit would make up the basic definition of a differential amplifier. Start with two input signals, and take the difference between their instantaneous voltage.
Or just invert one signal, then mix (add) it with the other signal? That's another way to create a differential.
if i have the P-MOS and N-MOS differential input, the equivalent small signal circuit of these circuits as in the figure bellow. So the question is, How can put these equivalent circuits together as complementary input
M1-M2 form a long-tail pair with I1. This is the core of the differential amplifier.
I1 has the effect of making it impossible for both M1 & M2 to conduct at maximum simultaneously. M1 might conduct a lot, and M2 a little. Or vice versa. But never both at maximum, even if both are biased to turn on fully.
Notice if M1 is conducting medium, and M2 then is turned on high, then it can cause M1 to conduct low or even to turn off. This interaction is not obvious from looking at a simple schematic. The interaction is not easy to predict. So it is not easy to predict what the output will be.
Your equivalent circuit needs to make I1 govern both M1 & M2, somehow. That is a chief principle in the differential amplifier.
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