Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

[ARM] Initialize the UART in lpc2138

Status
Not open for further replies.

soft_learn

Newbie level 5
Joined
May 22, 2014
Messages
10
Helped
0
Reputation
0
Reaction score
0
Trophy points
1
Activity points
69
Hi,

I am newbie learner to ARM7 processor LPC2138 n in which i am trying to interface UART to send a single character but it sends out unwanted character. If any one here knows about the UART of lpc2138 plz help me out.
My code is :

Code:
#include <LPC213x.h>
void UART0_Init(void)
{
    PINSEL0 = 0x00000005;                //P0.0 as TX0 and P0.1 as RX0
    U0LCR = 0x00000083;                                    // Enable Access to Divisor Latch
    U0DLM = 0x00;
    U0DLL = 0x00000062;                                    //Baud Rate of 9600
    U0LCR = 0x00000003;                                    //Disable Access to Divisor Latches
}

void UART0_Write(unsigned char c)
{ 
    while(!(U0LSR & 0x20));                        
    U0THR = c;
}


int main()
{
	UART0_Init();
	
		UART0_Write('A');
	
}
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top