julian403
Full Member level 5
Hello people. In the next circuit I need to find the average current in the load (battery which it's 10[V] and the resistor it's 0.5Ω and the inductor 6.5mH) and the thyristors are shoot at \[\frac{\pi}{3}\]
![asdf.PNG asdf.PNG](https://www.edaboard.com/data/attachments/70/70446-ec1a07edd16aaa76715e8071c74d81f7.jpg)
there is two modes of operation, 1 where T1 and T1 drives current and the second where those drives current because the inductor's current untill T4 and T3 are shoots.
So the differential equations it's
\[v(t) = i(t) R + L \frac{d i(t)}{dt } + 10\] and \[v(t) = \sqrt{2} 120 sin (2 \pi 60 t)\]
but what I don't know it's: I must put the signal v(t) in the equation because the thyristors are shoot at \[\frac{\pi}{3}\]
\[\frac{\sqrt{2} 120}{L} sin (2 \pi 60 t) - \frac{10}{L}= \frac{R}{L}i(t) + i'(t)\]
Solving that:
\[i(t) = -20 +86.4{e}^{-76.9 t} - 66.48 cos(376.7t) + 13.56 sin(376.91)\]
and here it's the graph:![Captura.PNG Captura.PNG](https://www.edaboard.com/data/attachments/70/70447-41243517d00d6b0c6d9e07cf38475e96.jpg)
But the problem it's the voltage in the load do not start at 0s but it's star at \[(\pi /3) /(2 \pi * 60)\]
The second mode it's
i[2*0.00277]= 81[A] to two to do not use the transient
![Captura3.PNG Captura3.PNG](https://www.edaboard.com/data/attachments/70/70448-9dbf27537fa478d7d49240adc4f46234.jpg)
The average current is:
\[60[Hz] ({\int}_{2*0.0027}^{2*0.0027+0.00877} {i}_{t}(t)dt + {\int}_{2*0.0027+0.0087}^{2*0.0027+0.0087+0.0027}{i}_{2} (t)dt)\]
So the average current it's 6.9[A] but the rashid says that the average current by the thyristor it's 44[A]
What do you think?
![asdf.PNG asdf.PNG](https://www.edaboard.com/data/attachments/70/70446-ec1a07edd16aaa76715e8071c74d81f7.jpg)
there is two modes of operation, 1 where T1 and T1 drives current and the second where those drives current because the inductor's current untill T4 and T3 are shoots.
So the differential equations it's
\[v(t) = i(t) R + L \frac{d i(t)}{dt } + 10\] and \[v(t) = \sqrt{2} 120 sin (2 \pi 60 t)\]
but what I don't know it's: I must put the signal v(t) in the equation because the thyristors are shoot at \[\frac{\pi}{3}\]
\[\frac{\sqrt{2} 120}{L} sin (2 \pi 60 t) - \frac{10}{L}= \frac{R}{L}i(t) + i'(t)\]
Solving that:
\[i(t) = -20 +86.4{e}^{-76.9 t} - 66.48 cos(376.7t) + 13.56 sin(376.91)\]
and here it's the graph:
![Captura.PNG Captura.PNG](https://www.edaboard.com/data/attachments/70/70447-41243517d00d6b0c6d9e07cf38475e96.jpg)
But the problem it's the voltage in the load do not start at 0s but it's star at \[(\pi /3) /(2 \pi * 60)
The second mode it's
i[2*0.00277]= 81[A] to two to do not use the transient
![Captura3.PNG Captura3.PNG](https://www.edaboard.com/data/attachments/70/70448-9dbf27537fa478d7d49240adc4f46234.jpg)
The average current is:
\[60[Hz] ({\int}_{2*0.0027}^{2*0.0027+0.00877} {i}_{t}(t)dt + {\int}_{2*0.0027+0.0087}^{2*0.0027+0.0087+0.0027}{i}_{2} (t)dt)\]
![Captura4.PNG Captura4.PNG](https://www.edaboard.com/data/attachments/70/70449-09123e7b1efa2389590be3f2be086baf.jpg)
So the average current it's 6.9[A] but the rashid says that the average current by the thyristor it's 44[A]
What do you think?