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Recent content by vadkudr

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    FPGA -AVR 3.3 - 5 volt level converter

    io level converter 1. If FPGA output are 5V tolerant - you can use it with 5V uC. 2. The best way is using atMega16L with supply 3.3V
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    FFT convolution - FFT resolution vs length

    fft length resolution Mathematically (I underscore - mathematically, i.e. equal) FFT convolution is nothing more than the fast algorithm to do linear convolution. You don't need to worry about stationarity interval, while you're performing linear convolution. If you process audio signal in...
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    how to extend 16 digital bits to 18 bit input of a DAC

    Multiplying signal by 4, you also multiply noise by 4. So SNR remains the same (16 bits is equivalent to 96 dB). It means that you added two (so named) "noise bits". They are really consist quantization noise,but not harmonic distortion or something similar what you mentioned. There is some...
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    Help Required Regarding Radix-8 FFT Implementation

    There faster algorithm h**p://www.fftw.org/newsplit.pdf Steven G. Johnson and Matteo Frigo, "A modified split-radix FFT with fewer arithmetic operations", IEEE Trans. Signal Processing 55 (1), 111–119 (2007).
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    Is this a causal system ?

    Re: Causality When integrating right part ∫x(t)dt variable t is disappeared. So you get only fixed number as a result. Your question is incorrect. Did you meaned y(t)∫x(s)ds ; Integration range: 0 to t ??? The this is causal system named integrator with reset function. Reset is...
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    Help me with coin recognition through image processing in Matlab

    coin recognizer MatLab Help Neural Network Toolbox Demo Appcr1: Character Recognition May this can help you
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    half-band filterdesign in matlab

    Re: half-band filter+ matlab See "firhalfband" **broken link removed**
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    req:algorithm for calculation of 10^x & abs(complex) &am

    Re: req:algorithm for calculation of 10^x & abs(complex) Ercegovac M.D., Lang T.(2004) Digital Arithmetic(709s).zip Koren I.(2002) Computer Arithmetic Algorithms(2nd Ed)(281s).djvu Muller J.-M.(1997) Elementary functions algorithms and implementation(218s).djvu
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    How to implement radix22 sdf fft using Verilog?

    Re: fft See this page for online verilog FFT generation https://www.spiral.net/hardware/dftgen.html
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    Image Super Resolution

    You can search through google book.google.com There is several books with 70% open contents. Unfortunately I have no other books. May be there is a way order itthrough the bookstore... I sent you private message consisting my e-mail for further discussion
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    Image Super Resolution

    I can give you some hints, though I only intended to study it in my free time. Unfortunately last several monthes can not find free time at all :-( There is severalbooks on super resolution 1. Super-Resolution Imaging : Subhasis Chaudhuri 2. Image Mosaicing and Super-Resolution : David...
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    HELP: CORDIC Timing optimize

    Strange, for generating triangle you can use simple reccurence a=a+step For which purpose U use CORDIC? It is originally developed for trigonometric functions. But in your post there is no mention of sin, cos etc... Please clarify your question
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    Fast alogrithm to implement DCT

    What type of DCT do you mean? Anyway, If you have fast algorithm for one of type of DCT (or evem for FFT) you can transform it to your DCT type Refer to (there are matlab codes for transformation between different DCT types and to FFT as well) **broken link removed**
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    Adaptive cancellation problem

    Input of adaptive filter - square wave Desired signal - mix of square wave and sin (both with unknown phases) Then output of adaptive filter will be square signal with the phase equal to phase of square in the mix error signal will be sin
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    What is the physical meaning of Z transform?

    Re: Z trnsform Z transform allows to analyze and handle infinite discrete (in time domain) signals. How to? Lets do mathematical trick - multiply k-th sample on z^(-k), and sum them. We get polynomial. Infinite one in common case. Multiplication of two polynomials is convolution of their...

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