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Dana,
thanks for taking the time to help me but what you ask is way over my capabilities.
I'm starting to think that what I'm asking is way far from my capabilities as beginner hobbiest, and should wait until I get more experienced to achieve this result.
Not to say that at 3,5 bucks at IC it...
Let's recap a bit as I've made a bit of confusion ( my bad ).
This is the inital schema:
A part for the type of capacitor ( polyester and not ceramic for 0.1uf and all other electrolytic ) there was a major error: C3 should have been 47uf and C4 should have been 100uf ( big error I suspect )...
Hard for me to see, but being a normal transformer I would even say 16.5 V
How can I measure a peak ( I don't have a DSO ) ? My tester says ( on AC ) 16.5V
You're right. Sorry. I've used polyester for 0.1uf ( and is wrong as per D/S ) I will change for ceramic ( If I've understood D/S ). All...
Hi Klaus.
Measured. 16.5 V AC
Kind of. I followed the instruction on the link I posted in my first post. Then I've read it, but ...
Read before. Followed the web page.
A big heatsink but it was not heat at all. I wasn't drawing current until I shorted the output and IC blown in a millisecond...
It's hard to say, but I bought the IC from a local electronic store, not from ebay or amazon where it could more easily a counterfait part.
Symptoms of failure has been some sparc from output connector, when I shorted them, and then no more output from the circut. Also powering off and then on...
Hello all,
I've found a nice circuit around, for an LM350T variable power supply, and I built it.
Here the link:
https://www.eleccircuit.com/lm350-adjustable-voltage-regulator/
I added a second pot, as indicated in the linked page, for a precision settings, and thus the circuit become this...
The storing in eeprom was only for debug purpose.
Now I have remove it completely.
The code showed was only to understand why it was bheaving different in two phases of program, but xenos got the right solution.
In the debug part I was using char, while in the main loop I was using int.
In the...
packet_bits[packet_bits_pos] = input_state(DI);
packet_bits_pos++;
This was the content of ISR ( also if it should have been input_state(DI)+'0')
No big caclulation I suppose ( also if this, translated from C to asm could have been more than a small calculation ;) )
Pigi
I have been told, in other sites, that an interrupt routin, in CCS and at 4Mhz with a pic16F628 costs 56us, the clock frequency is 8us.
Also moving to 20Mhz I could loose some clock. Am I right ?
In a while loop I should loose less time, or at least with a while loop ( and a 16F1826 at 32Mhz :)...
I have been told, in other sites, that an interrupt routin, in CCS and at 4Mhz with a pic16F628 costs 56us, the clock frequency is 8us.
Also moving to 20Mhz I could loose some clock. Am I right ?
In a while loop I should loose less time, or at least with a while loop ( and a 16F1826 at 32Mhz :)...
I have tried that, but it seems that PIC are not so efficent in handling the interrupts.
They take a lot of cpu cycle and the timing are very short.
I've computed that with a 16F628 (at 20Mhz) I was missing one or two clock cycle every interrupt.
IIRC the interrupts in PIC "costs" 4 cpu...
This is very interessant, and I whould think at it if I can adopt in my code.
I'm not reading from an uart, but from the tacho signal of a mill.
The protocol is based on 4 packet of 17 bits, controlled by a clock ( a kind of Spi, but different in some way ).
You can read about this protocol...
Hi all.
I' m wirting a code to decode a signal from a source.
The source sends out a bit train in this fashion: 10100000 10100001 10100010 10100011
In my code I read this data train and write it in hex in the internal eeprom.
I wrote the routine and checkd in mplab using some test code in...
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