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Use ground plane, power plane, multiple decoupling caps (for instance 1uf, 100n, 1n in parallel), smooth tracks without 90 degree angles, flip chip devices, match bus wire lengths, and match impedances for digital output to digital input (such as 10 ohm resistor in series).
Only way to find out is to build it. I don't see how to calibrate the 1.25V offset unless there is a DAC because the opamp needs this voltage reference. There may have to be a DAC or a trim pot for this.
Built-in digital outputs of accelerometer is 6 bits over the range of +/- 1.2G, this offers the resolution of less than arcsin(1/2^5) or about 2 degrees. If there was an 8-bit digital accelerometer, arcsin(1/2^7) is about 0.5 degrees. Both options seem insufficient for an electronic level. I...
You should just get an opto-isolator zero-cross chip they are much cheaper than a transformer. They usually output a pulse at zero-cross meant to drive a triac. This way you can keep a triac on without using firmware resources to maintain the triac on.
I suggest to avoid discrete h-bridge solutions because there becomes a margin of error. If you mess up any aspect such as shoot-thru current or overheating, you could ruin your motor, electronics, or power supply. Using a chip such as VNH3SP30TR-E protects you from mistakes and will fail...
FPGA dev is more unpredictable and harder to estimate and easy to run into complications. I would double my normal hourly rate knowing that some complication will make me work weekends to finish on time.
I suggest an opto-isolated zero-cross detector.
A cheaper more DIY solution is to use a series of 3 100k resistors (to protect from arcing) a 3.3v zener diode, and a regular diode that can block 300V+. The result will be a 50hz square wave 0-3.3v.
I want to make an electronic level based on an accelerometer. Is this possible to detect changes of 0.1 degree with an accelerometer?
The problem will be to condition the analog voltage of the axises. The accelerometer shows 0G voltage at 1.25V and 1G at 1.61V. To detect 0.1 degree it will...
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