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Recent content by kolahalb

  1. K

    What's the range of projectile in this task?

    Re: projectile problem Itis wrong. I have already done it. You have to consider it as a central force problem.
  2. K

    What's the range of projectile in this task?

    Re: projectile problem Yeah... The first part was wrong.
  3. K

    What's the range of projectile in this task?

    A projectile of mass m is fired from the surface of the earth of radius R at an angle α from the vertical with initial speed equal to (1/[sqrt 2]) the escape velocity.How high does the projectile rise?What is its range on earth's surface?Neglect air resistance and earth's rotation. I solved the...
  4. K

    Proving that curl of gradient of f=0 using Stokes' theorem

    Re: vector problem pmonon,proving was not the problem. The question specified to use Stokes' theorem.
  5. K

    Vector field question

    This is indeed a doubtful question and I am still thinking if it is correctly printed... However,given this is correct,I am trying this...
  6. K

    Proving that curl of gradient of f=0 using Stokes' theorem

    Re: vector problem Observe one thing-in case of magnetic field,you cannot in general put forward a scalar potential given by grad V. Here it is given... I have talked to 4-5 forums regarding this.None but you are still lingering with a problem that does not seem to be done in wrong method. Ok,I...
  7. K

    Proving that curl of gradient of f=0 using Stokes' theorem

    Re: vector problem cannot agree buddy! Think of Gravitational force...whatever path you follow the line integral is always dependent on end points..
  8. K

    Is this a valid question?

    OK,A and B are vector fields having curl equal to zero. We are to show div of (A+B)=0 Possibly the question is wrong.Except from some specific example it is not correct.Hence,cannot be proved. Actually,since I wanted someone to say with me that this is wrong, posted this over...
  9. K

    Proving that curl of gradient of f=0 using Stokes' theorem

    Re: vector problem The Fundamental Theorem of (Integral) Calculus is of the form: (Lower Lt a,Upper Lt. b) ∫(df/dx)dx=f(b)-f(a) where df/dx is often written as F(x). So,when you use a cyclic integral,it means you are tking both the lower and upper limit to be the same... We are bound to use...
  10. K

    Vector field question

    Basic silly conceptual mistake. rotational vector field means curl V is non-zero. It can also be understood by commonsense.Curl measures the amount of rotation of a vector field.So,irrotational means curl V=0 and rotational means curl is non-zero. k was also scalar when you extracted (f/k)...
  11. K

    Vector field question

    You are simply WRONG.V is a vector field and by question,the curl is non-zero. Added after 16 minutes: I mean if the question is correct,then you are wrong.But if the question is wrong then you are correct. Added after 22 minutes: It is not convincing.You have missed a term...(f/k) is...
  12. K

    vector analysis---WRONG!!!

    I did not understand why ∫div B dV is not zero.For a closed volume there is no magnetic monopole that will make the divergence non-zero.
  13. K

    Is this a valid question?

    I am to show that Ñ.(A+B)=0 if ÑxAis not=0 ÑxBis not=0 I suppose this is not a valid question.You please check.If it is a correct one then tell me how to start with. Added after 7 minutes: OK,that was a notation problem. What we are given is that curl A or curl B are not equal to zero.
  14. K

    Vector field question

    A vector field V is not irrotational.Show that it is always possible to find f such that fV is irrotational. curl [fV]=f curlV-Vxgrad f I have to equate the LHS to zero.But then,how can I extract f out of the resulting equation? Please help
  15. K

    vector analysis---WRONG!!!

    What is the wrong in the proof that there is no magnetic field? We know: div B=0 and B=curl A where B is the magnetic field and A is its vector potential Then,∫div B dV=0=∫B.n dA(divergence theorem) Thus, 0=∫(curl A).n dA =∫A.dr(Stokes' theorem) The last will be a cyclic integral. Since...

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