Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.
Clock mux in general makes the output glitch free. When both the clocks are low and the select signal is toggled; it switches output. If it works for clock; it should work for other signals as well.
The most critical signals like reset signals for flip flops and the control signal of various communication interfaces (CS/SS for the SPI) are often active low. What advantages do they bring over having an active high signal ?
My malloc is allocating consecutive addresses. I want my linked list next address to be a random address instead of consecutive addresses. I know malloc is hard to control; so i wanted to know how to randomize the pointers in the linkedlist? For exxample ; if link1->next = 0xf8 ; link2->next =...
I have a microcode assignment which has to be implemented in RTL, however, i am trying to build block by block but since there are highly interdependent on control unit, i am loosing motivation. So could anyone tell me how to proceed with such designs and any reference material would be...
In the CMOS VLSI DESIGN book by Neil H E Weste, section 4.5.1 states that the logical effort is independent of the size of the transistors, the electrical effort is dependent on sizing? I believe logical effort is dependent on transistor sizing? Can you guys help me with this ?
Thanks for the reply. After trying to understand, I am still not convinced how does it result in increase of a clock cycle, Pipelining means that Fetch and Excute of instructions happen in parallel in the same clock cycle. Why do we need to increase clock period for that ?
How does reducing number of clock cycles per instruction might increase the period of clock cycle? Can anyone please provide a clarity for this tradeoff?
I found this while reading the book Computer organization and design, RISC V edition, In the section 1.6 perfomance
@list_1 = (1,2,3,4,5,6,7,8,9,10);
@list_odd = @list_1[0,2,4,6,8];
@list_prime = @list_1[1,2,4,6];
foreach $x (@list_odd) { print @list_odd[$x];}
Output : 3 , 7
For some reason, it's not showing the remaining elements of the list. Can anyone help me with it?
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.
