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The problem is the capacitor sizes (In reality the voltages. 130nm devices will not survive 5V). If you change c1-c4 to 0.2pf it might show you what you expect.
Yes it is true. To get the correct bias point you use an inductor to break the feedback loop. The AC source should be applied to -("vin vref 0 1.22 AC 1"). The cap should be at + to GND. The reason is your input is vref. The gain is vref/vout. You want the + input to be at AC ground, hence...
The input bias current is pretty high, and your resistors are pretty large so that may be the problem. Do you have an input bias compensation resistor of RF||Rin?
I can not see your image, but your description sounds wrong. The inductor should provide a dc path, but an AC open. It should be in in series with the feedback path. The capacitor should be at the point of feedback to the error amplifier to provide an AC ground. The AC signal should be at...
You need to know the maximum allowed voltage for the oxide. The breakdown voltage is usually ~3x the max allowed voltage.
Running near the breakdown voltage will result in very short lifetimes.
Does this work. It does not on my old matlab but in up to date versions I think 64 bit integers are supported.
i=uint64(90030021002145212);
b=uint64(90030021003000000);
while(i<b)
fprintf('%u\n',i);
i=i+1;
end
This device is diode connected. At startup with zero current flowing the vgs will stay below vth (it does not need to be at vdd) when the power is applied slowly.
Re: Converting an analog input called "SPEED" (level=24V) to a signal suitable for MO
I think the circuit could be ok with 3 changes. 470k to 400k, 30k to 100k, and a pull-up resistor of 6k. The filtering on the signal is already very high. What kind of signal is it. I assumed just a...
Re: Converting an analog input called "SPEED" (level=24V) to a signal suitable for MO
1.4V nominal gate drive is too low. Especially if you consider the room temp threshold can be 1.5V, the divider tolerance could be large, and the 24V likely is +/- 5-10%
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