:arrow:similar question!How there can be an unknown at the port when ports are given Low or High?
How can x-propgate when ports are given Low or High?
If you accidentally connect two gate outputs together, and they are driving different values, the combined output signal will be 'X' in simulation. In a real circuit, the output can be '0', '1' or something in between, so maybe you don't see anything wrong with the output signal, but there is an error in the design.How there can be an unknown at the port when ports are given Low or High?
How can x-propgate when ports are given Low or High?
I don't have much experience with gate level simulation, but for shorted outputs I think it will be identical to RTL simulation.Hello std_match
Will the x also be realized in gate level simulation? Is it that in this case of two outputs shorted together, the gate level simulation will also produce 'x' as the RTL simulation produce 'x' ?
Regards
There are no shorted outputs in that code. It is only about 'X'-propagation, and it seems to be a case where a difference between RTL simulation and gate level simulation is expected.Then how do the page 9 in attached paper talk about simulation and synthesis mismatch for casex and casez?