Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Why is the VGS of a diode-connected MOSFET relatively supply-independent?

Status
Not open for further replies.

aravind2705

Newbie level 1
Joined
Dec 31, 2011
Messages
1
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,288
Capture.PNG
For example, in the Beta-Multiplier circuit I have attached here, when I sweep the VDD, the VSD of M4 increases at a higher rate than does the VGS of M2.
Also, the gate of M3 follows VDD and keeps VSG constant. Why does this happen, Why is the gate-source voltage of a diode-connected transistor magically supply-independent (in the large-signal domain) ??

Image: https://obrazki.elektroda.pl/84_1325303679.png
 

You can think a diode connection (gate connected to drain) as a local feedback loop.
Imagine Vgs as the input and Vds (= Id * Rload) as the output: raising Vgs causes Vds to decrease.
When you close the loop (Vgs=Vds) the net effect is to "lock" Vds to Vth (at first order).
This behaviour is probably more evident for BJTs.
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top