Why is base current not what it should be?

Status
Not open for further replies.

arjob

Newbie level 6
Joined
Mar 18, 2012
Messages
12
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,346


My multimeter shows:
Ib=218\[\mu\]A why?

But my calculation shows, it should be: 8.5\[\mu\]A

I used the formula:
Ib=(3.1-0.7)/(10k+271k) [I have \[\beta\] = 270 ]

What is the problem? Please help
 

The equation which you used is accurate when the transistor is operating in active region. I mean, the current gain or beta value of a transistor at saturation region is different from that at active region, which is less than the former. It means, you cannot put the value as 270, but a lower value. which will cause a higher value of base current. In short, you should know where your BJT is actually operating in; active region or saturation region, and put appropriate value of beta.
 

with R5 = 100 k, the transistor is saturated, with a current of 3.1/101K through its collector circuit, so there will be a lower voltage dropped across R4 (30 microA X 1K ~ 30mV), so the current is about 3.1 -.7V /10K.
Frank
 

Yes, thanks. I realized the mistake I was doing in calculating the Ib.
 

Status
Not open for further replies.

Similar threads

Cookies are required to use this site. You must accept them to continue using the site. Learn more…