hi, you knew that i=u/r...........(1) and p=r.i.i............(2)
when you make short so r= 0.00000000001, .............(1)
than we put r in...(2) so we find a very high value of i , than the fuse blow
imagine i have voltage source and resistance and capacitance in series, i am applying DC voltage and current flows upto resistance and the inductive capacitance is infinity so ,it is open,my question is where the current will go its not a complete one??Y can any one clarify?