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if all the resistors in the network are the same,
i think the equivalent R is R1/4
you can put the pb in this way: as the network is infinit, at point A, the 4 directions are all the same, so with an input current of Iin at A, there will be only 1/4 Iin going through R1.
so the votage drop on R1 is (1/4 Iin*R1), where comes from the answer
The equivalent resistance between the terminals is A and B is R1/2 and the resistance seen by R1 will be R1(ie resistance of each branch if they are equal and equal to R1).
The norton s theorem should be applied to this ckt
if all the resistors in the network are the same,
i think the equivalent R is R1/4
you can put the pb in this way: as the network is infinit, at point A, the 4 directions are all the same, so with an input current of Iin at A, there will be only 1/4 Iin going through R1.
so the votage drop on R1 is (1/4 Iin*R1), where comes from the answer
Hi
I think R/2.
Assume that infinite has potential of zero.
Place the voltage source A between zero potential and node A.
the current of source sees 4 paths that all of them are the same.
so there is a R/4 ohm between node A and zero potential.
Do it for node B, there is a R/4 ohm between node B and zero potential, too.
so there is R/4+R/4=R/2 between A and B.
regards
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