why current drop in pwm
The voltage drop input-output? That's the step-down
ratio which becomes roughly the PWM duty cycle,
VOUT/VIN. The drop is (duh) VIN-VOUT.
The voltage droop, or load regulation, is pretty much
just the error amplifier (and powertrain) composite
gain as a chopped transconductor. If you are current
mode controlled then you have a volts-in, current-out
relation somewhere in there (say, 1A/V) and a volts/volts
error amp gain (say, 60dB=10,000). So at the error amp
input you would see for a 1A load step, a 1/10,000 (or 0.1
mV) input deflection. Now scale that up by the feedback
network ratio (say, 5:1 for a 28V to 5V buck) and you get
a 0.5mV output deflection. All happy, right?
Well, probably not. A major, major term in load regulation
is the current induced offsets in the ground and the feedback
lines, which develop current-dependent error voltages. If
the load current return and the PWM ground are offset,
this may go right into the error amp (prime reference is
chip ground, != package, !=board ground). You would like
a Kelvin ground and load sense, but this is not always a
practical thing.