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What dc can u measure?

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Justin18

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Which DC can you measure according to picture a, b, c?

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i think 19,8V because a diode needs 0,7V so 20,5V-0,7V=19,8V. I dont know if its right.
 

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No, sine peak voltage is sqrt(2)*Vrms (designated Veff in the picture).

Without further information we should assume sinusoidal waveform.
 

assuming sinusoidal waves, and since there is no apparent load, all three circuits act as peak detectors.

If Veff is Vrms, then Vpeak = sqrt(2) * Veff or Vpeak = sqrt(2) * 20,5 V = 28.99 V

remove the 0.7 V diode drop yields 28.3 V

Since the drawing asks for Uab, point b is the reference
the top drawing would measure +28.3 V
the middle and bottom drawings would measure -28.3V because the diode is in the opposite direction,
making b the more positive location
 

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