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What dc can u measure?

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Justin18

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Which DC can you measure according to picture a, b, c?

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i think 19,8V because a diode needs 0,7V so 20,5V-0,7V=19,8V. I dont know if its right.
 

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FvM

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No, sine peak voltage is sqrt(2)*Vrms (designated Veff in the picture).

Without further information we should assume sinusoidal waveform.
 

wwfeldman

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assuming sinusoidal waves, and since there is no apparent load, all three circuits act as peak detectors.

If Veff is Vrms, then Vpeak = sqrt(2) * Veff or Vpeak = sqrt(2) * 20,5 V = 28.99 V

remove the 0.7 V diode drop yields 28.3 V

Since the drawing asks for Uab, point b is the reference
the top drawing would measure +28.3 V
the middle and bottom drawings would measure -28.3V because the diode is in the opposite direction,
making b the more positive location
 

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