WCDMA signal bandwidth

[brmadhukar]

wcdma bandwidth

The signal bandwidth for the W-CDMA system is set at 5 MHz. This high bandwidth allows the received signal to be split into distinct multipaths with high resolution.

What does this mean?

TIA
B R M

 

[eda4you]

wcdma chip rate

That simple the principle of CDMA. The higher the bandwidth --> W-CDMA, the more resolution or channels you have, respectivley..

 

[brmadhukar]

bandwidth of wcdma signal

Hi,
How do you get more resolution between the channels. The chipping rate is fixed at 3.84MHz. That was the question.
B RM

 

[ninhawk]

signal bandwidth

just my 2cents:

greater bandwidth ==> highest sample rate ==> greater 'time resolution'

so, for example, if you have 5Mhz BW and your sample rate is 10Msps then, you can resolve multipaths delayed 100ns (1/sample rate). So you can take the benefits of a great number of multipaths (using the RAKE receiver) than a system with minor bandwidth.

regards

 

[brmadhukar]

wcdma rrc filter

Hi,
Suppose I have 1.25MHz bandwidth, I can still sample at 10MHz right? Then how?
TIA
B R M

 

[sourour]

wcdma band width

Resolution depends on the chip rate. In WCDMA the chip rate is Rc=3.84 Mcps. hence, the chip duration is 1/Rc=0.26 usec. Hence, the receiver can resolve (i.e, distinguish) any two paths with relative delay > 0.26 usec. This is done using the code matched filter.

The bandwidth depends on the pulse shaping filter used. The root raised cosine filter used in WCDMA gives a 5 MHz bandwidth.

 

[sachinlan]

chip rate wcdma

You have to consider spectral efficiency.
i.e. Spectral efficiency = Signal bandwidth/ Chip rate.

Here signal bandwidth is 5 MHz and chip rate is 3.84 Mcps.