no, that won't be acceptable.
SSI is based on RS-422 using using 24 AWG Standard, copper conductor, unshielded twisted-pair telephone cable with a shunt capacitance of 52.5 pF/meter (16 pF/foot) terminated in a 100 Ω resistive load.
Thus to limit voltage, examine the source resistance and load resistance to determine what series resistance is needed to limit the voltage. Many uC's now have 25 ~50 Ω sources.
Even if the pin is one way communication? I thought that maybe a single diode in the pin's direction and a pull-up resistor would be enough.You need two diodes so that the signal fall-time is not seriously degraded.
Put the two Schottky in inverse parallel and connect the two in series from the 3.6V output to the 3.3V input.
For that I need to check the input impedance of each pin. Can't find it on the datasheet, or I am looking in the wrong section.To reduce the signal level a little then why not use a voltage divider made with two resistors in series?
Yes, the slew rate is too low, the clock period is higher than the time needed for the op-amp to present 3.3V on its outputLM358 has similar input specifications as the digital circuits and isn't suited for digital signals like SPI at all. It doesn't even achieve a sufficient high output level.
I presume you are working with CMOS devices which have effectively infinite (high MOhm) input resistance. Voltage divider or series resistor values are more imposed by IC and wiring capacitance, at least for higher SPI data rates. A low kOhm range is usually appropriate.For that I need to check the input impedance of each pin. Can't find it on the datasheet, or I am looking in the wrong section.
The communication may be one-way but the signal goes high and low. Two diodes will allow the driver to drive the signal high as well as drive it low, minimizing any rise/fall time degradation of the signal....................
Even if the pin is one way communication? I thought that maybe a single diode in the pin's direction and a pull-up resistor would be enough.You need two diodes so that the signal fall-time is not seriously degraded.
Put the two Schottky in inverse parallel and connect the two in series from the 3.6V output to the 3.3V input.
..........................
What if I use a scheme where I would connect the 3.6V pin in series with a Schottky diode and a 10k resistor. The voltage in the resistor would be 3.3V or less. How about that?
At he signal lines a diode and a pull down could also drop signal voltage.
I will test almost everything suggested, and I also came up with an ideia.
What if I use a scheme where I would connect the 3.6V pin in series with a Schottky diode and a 10k resistor. The voltage in the resistor would be 3.3V or less. How about that?
Hi,
What are you referring to? Why do you talk about SSI and RS422? Maybe i missed something?
Klaus
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