Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

voltage and current sources

Status
Not open for further replies.

jinyong

Newbie level 6
Joined
Jan 24, 2006
Messages
12
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,364
How come you can short ideal voltage sources and treat ideal current sources as open circuit.
 

jinyong said:
How come you can short ideal voltage sources and treat ideal current sources as open circuit.

If the R series of voltage source is very low compared with the circuit
If the R paralell of courrent source is very high compared to the circuit.

In this conditions you can simplifie the expression removing courrent source and short
voltage power.
If not you need to include then in the circuit

Regards
 

If you're doing a signal analysis of a circuit, you can simplify the analysis considerably if you separate the AC and DC analysis. Afterwards, if you want to get the total results...you just apply superposition (add your DC and AC results).

Thus, when we go for a signal analysis we set the value of the ideal DC voltage source to ZERO; a voltage source of 0 volts is equal to a short circuit b/w it's terminals.....b/c current due to some other source can still pass through it without any voltage drop (a simple ideal wire has the same property - thus ideal 0 V voltage source = ideal wire).

Similarly, in the signal analysis (applying superposition) we can simply eliminate (set to ZERO) the current source.... A current source of 0 A ... does not allow any current to flow through it... and is therefore said to have infinite resistance.
 

let's think of it this way:
since it is ideal VS or CS then,
- the resistance of the VS is very small in series...and it is considered to have 0 V as drop so it is a short circuit
- the resistance of the CS is very large in parallel..and it is considered to have 0 A as current so it is an open circuit
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top