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Vctrl of VCO in PLL, so strange!

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lifusu

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hi guys!
i design a pll (verilogA), 12MHz input , C2=400p, C1=40p, R2=3.3k,bandwidth=600k,Kvco=600MHz/v,Icp=20uA,when locked , the wave of Vctrl is as follows, why the Vctrl like this? i don't think it is ripple.
But when i delete divider, this condition will not occur, but the divider is ideal , why?
thx in advance!
pll.png
vc.png
vc2.png
 
Last edited:

another Q.
when i set the Vctrl 0v initially, the wave is as Fig.1;
when i set the Vctrl 0.5v initially, the wave is as Fig2.


0v.png
0.5v.png
 

I don't know the software you are using but I would suggest you adjust the simulator settings - the erratic results look like timestep problems. Reduce the value of the maximum timestep.

Keith
 
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    lifusu

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are you using any initial condition for your rc filter. try to use some 0.5Vlts to your filter as initial voltage.
Show us the AC response of your model.
 

I am using spectre and just as you said, it is really timestep problems! Thank U so much!
and also thank varunkant2k!
 

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