dipnirvana
Full Member level 4
- Joined
- Jan 23, 2009
- Messages
- 210
- Helped
- 26
- Reputation
- 52
- Reaction score
- 4
- Trophy points
- 1,298
- Location
- India
- Activity points
- 2,296
Hi, all,
i have doubt which i didn't had earlier . Any way for one of my application i need to design gate driver of IGBT IKW60N60H3 (data sheet attached) . Drain current is 30A, drain voltage is 400VAC. now we have requirement of turning on the IGBT in 50ns ..yes that fast. Now if i go by my old way of calculation which says that Gate charge /time is equal to gate current.
So in this case gate charge is 375nC and time is 50nS. So gate current required is 375/50= 7.5 A . Now confusion is there because of the graph in datasheet , i am referring to figure 10.in that at Rg=6 ohm , td(on)+tr = 50ns . So in effect there is huge difference of current requirement . that is through this graph only 2.5 A is sufficient to turn on the IGBT in 50nS. Please note that in my case Vg =0 --> 15V.
Please help to clear the cloud.
i have doubt which i didn't had earlier . Any way for one of my application i need to design gate driver of IGBT IKW60N60H3 (data sheet attached) . Drain current is 30A, drain voltage is 400VAC. now we have requirement of turning on the IGBT in 50ns ..yes that fast. Now if i go by my old way of calculation which says that Gate charge /time is equal to gate current.
So in this case gate charge is 375nC and time is 50nS. So gate current required is 375/50= 7.5 A . Now confusion is there because of the graph in datasheet , i am referring to figure 10.in that at Rg=6 ohm , td(on)+tr = 50ns . So in effect there is huge difference of current requirement . that is through this graph only 2.5 A is sufficient to turn on the IGBT in 50nS. Please note that in my case Vg =0 --> 15V.
Please help to clear the cloud.