to solve equation using matlab

[shenba]

ωΛ4-1952.1ω²+548880=0 to spove this equation i need matlab coding

 

[Communications_Engineer]

I don't really get what you are asking but if it representing this equation as matlab code that here it is:

output = omega.^4 - 1.952.1*omega.^2 + 548880

output == 0

If the answer is 1, equation proved

Note: the program will work when omega is a scalar or a vector

the test condition when it is a vector can be given as

sum(output) == 0

 

[JoannesPaulus]

the matlab command is "roots":

roots([1 0 -1.952 0 548880])

ans =

-19.259288149555253 +19.233933035850992i
-19.259288149555253 -19.233933035850992i
19.259288149555260 +19.233933035850999i
19.259288149555260 -19.233933035850999i

I hope it helps!

 

[rfboardengineer]

"ωΛ4-1952.1ω²+548880=0 to spove this equation i need matlab coding"

Substitute u = ω²

u^2 -1952.1u + 548880=0 ; Now its quadratic

Is there more to this question?