A thermocouple by itself outputs a small voltage. If you are talking about the thermocouple amplifier/ adaptor, then you can simply load its output with a fairly large resistance (1-5k) and watch its output. If it changes significantly, then it's most likely a current-output one. If there is no change, then it is a voltage-output model.
the output for thermocouple is in mV
here is one table for many types of thermos (B...to T) and PT100 (100...to 1000). the language is PT but you are going to understand it.
Do you have a mV ? at least you can verify if they are damaged.
so how bout i want to test whether my thermocouple is still function o not... i construct a circuit for it and the measurement i get unchange although i put in hot water....
so how bout i want to test whether my thermocouple is still function o not... i construct a circuit for it and the measurement i get unchange although i put in hot water....
A thermocouple is a device based on Seebeck effect. It will generate a small potential if there is a temperature difference between a "warm junction" and a "cold junction". Standard thermocouples have only the warm junction and two wires. You have to find first what type of thermocouple do you have, because an platinum-rhodiu thermocouple will not deliver any measurable potential imersed in boiled water.
For this sort of measurements you need a copper-iron thermocouple or a copper (or platimum) resistor which is a different device. Or better a DS18B20 or a LM75 or a LM135 or a TC77 or KTY which are semiconductor thermometers.
the picture below are my connection of my thermocouple amplifier, why i only get 5.4mV when it is in ambient temp ? it suppose to take around 200mV? if i use lighter to heat it also remain 5.4mV, my connection is it got problem? i using AD595 thermocouple amplifier and connect accoding the data sheetgiven, anyone can guide me what is the prblem actually?