Advanced Member level 2
This transistor does not have max junction temperature listed but has derate value 267mW/C and power dissipation 20W. Is there any way to obtain its thermal resistance junction from case from listed parameters?
Thereby 20watts / 0.267derate = 74.906367 this is over 25c ambient which makes permissible junction temperature at 99.906367C. This is what you were referring to as 100c max?Yes, the derating number is equal to thermal impedance. It's by the way referring to Tj,max of 100°C.