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The signal at each differential output terminal is centered around Common mode voltage point with 180degree out of phase. But when we talk about differential signal is it centered around zero or common mode voltage?
Common mode amplifier is setting the output common mode voltage (Vout_p + Vout_m)/2 to Vocm reference. Differential voltage Vout_p - Vout_m only depends on the input signal.If you are asking about Vout_p - Vout_m, then obviously it is around 0.
I am asking about differential so yea it is " Vout_p - Vout_m" . It means if i want to see maximum allowable swing for output should i take the swing from 0 , right?If you are asking about Vout_p - Vout_m, then obviously it is around 0.
in figure you can see i get differential output of amplifier which is centered at 0. The supply voltage vdd is 1.2v so output saturates around 1 V. My simple question is that if i take differential output will it be centered around 0 volt or output common mode voltage set by CMFB stageHi,
From what "0"?
If Vout_p = Vout_m then Vout_diff = 0. Is this what you mean?
If not: please provide a drawing.
Klaus
We can't see if the waveform shows differential output or anything else. But as already stated, the differential output isn't affected by CMFB circuit. It solely depends on the amplifier input signal. Unfortunately you don't show the signal source connected to the amplifier, so it's an almost useless discussion.in figure you can see i get differential output of amplifier which is centered at 0. The supply voltage vdd is 1.2v so output saturates around 1 V. My simple question is that if i take differential output will it be centered around 0 volt or output common mode voltage set by CMFB stage
?
I am asking about differential so yea it is " Vout_p - Vout_m" . It means if i want to see maximum allowable swing for output should i take the swing from 0 , right?