CG
Newbie level 1
Hi, I'm planning on getting started back into the whole PIC thing.
Few years ago, I was playing with 16F84 and 16F628 in a mech. class. I used Microcode Studio and with some Melabs programmer(forgot which). Unfortunately, I forgot everything.
I was browsing around the other day, and found a few JDM programmers that are cheap(programmers used to be upwards of 100 bucks), so I decided to try playing with pics again. Right now, I have on order 2x 16F877 (they're not samples from microchip), and various crystals(still need ceramic caps).
Anyways, I'm starting out completely clueless about pics again, and I'm stuck with a couple problems:
which software should I use? looking online, I see people using winpic800, ic-prog or epic. which would be the best for my 16f877?
also, I was planning out the blinking led project and I calculated that i need ~130ohm resistors, but websites online say that you need 470-600ohm resistors.
Why?
I calculated as follows LED amp = .025A, Vsource = 5V Vtarget = 1.7V.
So V = IR, we get:
.025*130 = 3.3V
5V - 3.3V = 1.7V
Did i do something wrong?
Few years ago, I was playing with 16F84 and 16F628 in a mech. class. I used Microcode Studio and with some Melabs programmer(forgot which). Unfortunately, I forgot everything.
I was browsing around the other day, and found a few JDM programmers that are cheap(programmers used to be upwards of 100 bucks), so I decided to try playing with pics again. Right now, I have on order 2x 16F877 (they're not samples from microchip), and various crystals(still need ceramic caps).
Anyways, I'm starting out completely clueless about pics again, and I'm stuck with a couple problems:
which software should I use? looking online, I see people using winpic800, ic-prog or epic. which would be the best for my 16f877?
also, I was planning out the blinking led project and I calculated that i need ~130ohm resistors, but websites online say that you need 470-600ohm resistors.
Why?
I calculated as follows LED amp = .025A, Vsource = 5V Vtarget = 1.7V.
So V = IR, we get:
.025*130 = 3.3V
5V - 3.3V = 1.7V
Did i do something wrong?