so seems that your equation has no solution.
That can be easily verified:
You are using matlab, right (It is so expensive, I just use octave)? Plot the left hand side as a function of x; also plot the right hand side as a function of x. The point where they intersect is the solution.
You need to plot several times and expand to see that the intersection is real. That will give you a rough idea.
Wolfram Mathematica.excuse me i cant understand what does it do ??
can i ask what the software is ?
Real value solution for x can not exist.Using albbg idea:
assume a, b, c are real: then left hand side is real but the right hand side is imaginary (contains j)
if you want a real solution x must be real;
Such closed form solution can not exist for your nonlinear equation.a,b are real and are given by question a = 50 , b=-1 ;
now we wanna write(modify) x as a function of c : x=X(c);
then the albbg idea does not work.
Real value solution for x can not exist.
x must be complex number..
Do you really think so ?As the OP has supplied the both a and b, you can see the equation(s) has a solution;
In fact this is a pair of equation (because of j) and the LHS is equal to RHS equal to ZERO
You can plot the left hand side as a graph and see where it intersects the zero line.
You can also superimpose the plot of RHS (for several values of c) on the same graph.
Do you really think so ?
RHS is -j*c*tanh(x)/x.
-j*c*tanh(0)=0.
-j*c*tanh(0)/0=-j*c.
.
I'm sorry but for x real and c <> 0 a soltution does NOT exist.
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