Re: Single Supply op+Missing DC Bias Current Return when AC
Thanks for the reply....
i think i understood somewhat.....I want to share it, to know whether it is correct or not.
In both the circuits, we know bias currents flow continously.
In the circuit without R1, the capacitor will charge continously upto some point(i don't exactly upto what point it can charge) which will induce errors in the Output of the opamp.
where as in the circuit with R1 there is always path for the DC currents to flow to GND through R1 . So, i think most of the Bias current will now flow through R1 to GND. So that capacitor C1 will be charged to less extent(i don't know to which extent) which will reduce the errors.
is it right..?????
I think, in my graduation i have studied wrongly regarding capacitor.
as per the equation i = Cdv/dt
for DC voltage i = 0; so, capacitor blocks DC voltage
for DC current V = integral(I/C)dt which will increase linearly(this is wrong case)
Because, if DC voltage exists DC current also exist with it.
So, for DC, Capacitor is Open circuit, Current will be zero and voltage across the capacitor will be DC voltage magnitude(i.e if DC of 5V applied current through Capacitor is zero and one plate will be charged to 5V and another plate will be charged to -5V)...
thanking you,