Simple probability question

[safwatonline]

hello,
i have a small question in probability,
say i have a variable X that can be 4 values (A,B,C,D)
and a variable Y that can take 3 values (A,B,C)
and a variable Z that can take 5 values (A,B,C,D,E)

how many combinations can i get when i must choose one value at least of each values (i.e. an example combinations can be X=A ,Y=A,Z=A and X=B, Y=B, Z=E
note that in each combination each variable must be choosen once.

 

[ahmed_nasr]

probability

i think simply u can get 60 combinations = 4*3*5

and what does this have to do with probability ?

 

[hakeen]

Re: probability

For each possiblity (assuming the three X Y Z are independent of each other)

4 times 3 times 5 = 60..

Since combination can be mentioned as a part of probability, it is normal to ask this under probability title

 

[lay2ie]

Re: probability

60 is the solution