scanf formatted input %nand %p specifiers

[sathish.b]

conversion specification

what's the use of %n & %p in scanf...
plz tellme anybody know about this
please explain with example...with output also....

thank u for replying in advance[/b]

 

[sshahid47]

Hi,

you use %n in scanf for getting the integer equal to the number of characters read so far

eg:

int n = 0;
char str[100]={0};
scanf("%s %n",&str,&n);

if you now input the following to this program

abc<enter>
a<enter>

then

str = "abc"
and n=4, indicating that till now 4 characters has been entered i,e a b c and a.


you use %p to read the pointer value from the input

eg:

int *c=0;
scanf("%p",&c);

if you input the following to this program

1) abc, then the value of c will be 0x00000abc ,

2) absss, then the value of c will be 0x000000ab, note that it ignored sss coz they are not valid hex codes.

hope that clears up for you.