so the XL4015 is like the switcher IC that drive the MOSFET at hot area in SMPS. It provides the chopping voltage for current/voltage regulation.it fills in the gaps between current pulses from the XL4015.
Yep, I know this sequence of charging the inductor and that it charges up with current and the magnetic field collapses in a reverse direction.When the internal switch between VIN and SW is closed, current flows straight through , then through L1 to the output. In doing so, a magnetic field builds up around the core of L1. When the internal switch opens the SW pin becomes disconnected inside the XL4015 and with no current passing from it, the magnetic field in L1 collapses.
My question here, is where the current passed through D1 goes ?The polarity of voltage across L1 is reversed from then the field was created, this makes D1 conduct and the energy from the magnetic field is added to VOUT.
Yep, got this part, so normal diodes are used in SMPS bridge rectifiers, because they run at 60Hz, but when considering frequencies more than kHz the Schottky diodes are the one that can be counted for.All this happens very fast, the XL4015 switches at 10s of KHz. The diode is a Schottky type because unlike normal diodes, they store very little charge across their PN junction and that allows then to start and stop conducting very rapidly. Obviously this is essential when the switch is operating so fast.
Why to keep the diode current continuous ? where should the diode pass a current ? from the circuit diagram, the current should go to ground rail.thus keeping the diode current continuous
who would the choke raise the output voltage if it has a collapse current in reverse direction ?due to the ability of the buck choke to raise its voltage ( to quite high levels )
what would interrupt the current ?to keep its current flowing if it is interrupted ...