gbugh
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Is anyone in this forum familiar with Huff & Puff frequency stabilizers?
I'm trying to get my head around how a fast huff & puff frequency stabilizer works. I'm familiar with huff & puff designs or at least I thought I was until I started studying them more closely. Reference: http://www.hanssummers.com/huffpuff/library.html
The fast huff puff uses a shift register delay while the original huff puff design did not.
But while trying to design a fast huff puff for VHF frequncies it seems like some things don't add up.
One article says:
"The formula for step size is:
Step = 10^6 x VFO^2 / ( z x M x xtal)
where VFO is the VFO frequency in MHz,
z is the number of stages of delay,
xtal is the crystal reference frequency in MHz, and
M = 2^n where n is the number of divide-by-2 stages in the VFO divider."
However, other articles say that to maintain a constant step size as the VFO frequency is tuned that a person needs to swap the D and the Clock inputs into the D flip flop used as a digital mixer. That would be swapping the xtal based input with the VFO based input.
That is what is hurting my head because the above formula will never allow the step size to remain constant regardless of which feeds which input since both frequency sources are part of the formula and only one of them changes. The xtal base frequency never changes and the VFO frequency always changes so the step size must change regardless of swapping the 2 variables in the formula.
It seems like if the xtal based frequency clocks the D-flip flop and the shift register instead of the VFO based frequency then the D flip flop and shift register output values would change at the constant xtal based rate and it seems like maybe that would make the step size constant but the formula doesn't allow that to happen.
Is this formula correct? Is there a better formula some place?
Maybe the persons saying the step size would be constant were just wrong in their thinking?
I'm trying to get my head around how a fast huff & puff frequency stabilizer works. I'm familiar with huff & puff designs or at least I thought I was until I started studying them more closely. Reference: http://www.hanssummers.com/huffpuff/library.html
The fast huff puff uses a shift register delay while the original huff puff design did not.
But while trying to design a fast huff puff for VHF frequncies it seems like some things don't add up.
One article says:
"The formula for step size is:
Step = 10^6 x VFO^2 / ( z x M x xtal)
where VFO is the VFO frequency in MHz,
z is the number of stages of delay,
xtal is the crystal reference frequency in MHz, and
M = 2^n where n is the number of divide-by-2 stages in the VFO divider."
However, other articles say that to maintain a constant step size as the VFO frequency is tuned that a person needs to swap the D and the Clock inputs into the D flip flop used as a digital mixer. That would be swapping the xtal based input with the VFO based input.
That is what is hurting my head because the above formula will never allow the step size to remain constant regardless of which feeds which input since both frequency sources are part of the formula and only one of them changes. The xtal base frequency never changes and the VFO frequency always changes so the step size must change regardless of swapping the 2 variables in the formula.
It seems like if the xtal based frequency clocks the D-flip flop and the shift register instead of the VFO based frequency then the D flip flop and shift register output values would change at the constant xtal based rate and it seems like maybe that would make the step size constant but the formula doesn't allow that to happen.
Is this formula correct? Is there a better formula some place?
Maybe the persons saying the step size would be constant were just wrong in their thinking?