well, if i use 0.1% resistors i have an inaccuracy of max. 4mV:
Acl=-Rf/Ri -> (10K*1.001)/(10K*0.999)=1.002
input voltage is 2V so the output voltage is 2*1.002=2.004 that is an inaccuracy of 4mV. The ADM8660 doesn't need the gain setting resistors but i am wondering what the "voltage conversion efficiency" means, as i said is was 99.96%. so that would mean that if the input voltage is 2V the output voltage is 2*0.9996=1.9992. The inaccuracy of this is 0.8mV that would be enough. But i dont know if there are more factors that have an impact on the inaccuracy
greets rudie