#### FreshmanNewbie

##### Full Member level 6

I assume its a buck converter. In that case, on page 16 of the datasheet, Equation 4.1, There's this formula. Rvout = 8.2kohm * TRIM. If TRIM is 5, Then what would be the value of Rvout? Would it be

8.2kOhm

*5%= 0.41kOhm or 8.2kOhm*5= 41kOhm. What happens when I like to increase more than 5 %?

Can someone please explain?

Also, there is increased ripple when 41kohm is used in series. Can someone also tell me how to reduce this.