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I assume you have a calculator, or something like that ..
Here you will find the relevant formula:
"Inductance of a single-layer close-wound air-cored coil" **broken link removed**
Regards,
IanP
BTW. Just remember to add wire diameter (gauge) to the coil's diameter ..
Danny-
"but what does "18 gauge" means?"
There are several wire gauge standards and it would depend on which standard was used when the coil size was defined. I would generally assume that the American Wire Gauge (AWG) standard would be used which would make 18AWG wire 0.0403 inches or 1.02362 mm in diameter. You can do a Google search for 'wire gauge' and get several explanations/charts to explain further.
" former with 3/8" " means the coil diameter is 3/8 inches (without the wire diameter)? "
This means that the "former",or the form that you wound your coil on, has an outside diameter of 3/8". This gives your coil an inside diameter of 3/8"
You left out one important dimension to actually be able to calculate the value of the inductor you have described and that is the length of the coil. Without that you can not calculate the inductance.
There is a program which you can download at <http://www.dl5swb.de/html/mini_ring_core_calculator.htm> which can help you in your calculations. While it is primarily intended for developing toroid inductors, there is also the capability to calculate air core inductor values.
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