Question regarding Walsh Codes

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moonnightingale

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The book says
Lets suppose four Users are generating 1, -1, -1 and 1. Assign four different Orthogonal
Wash codes to each user. Each Walsh code should have eight chips.

Can anybody help me
What i understand each walsh code will have 8 elements
w0= 1 1 1 -1 -1 1 -1 1
w1=
w2=
w3= similarly

is this approach right.
 

Walsh code starts with an elementary matrix, H(0) = [1 1; 1 -1], to get H(m+1) = [ H(m) H(m); H(m) -H(m)], to get eigth chips code, you need 3 iterations. What's the problem ?
 

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