Neons and LEDs work in a completely different way. A typical Neon lamp works on about 90 Volts at a current of about 0.5mA whereas an LED works on about 1.5V at 10mA. Neons also light up regardless of the polarity while LEDs are damaged by just a few Volts in the wrong direction.
To adapt your circuit, remove the capacitor and the 160K Ohm resistor completely and replace them with a diode (1N4006 or similar), facing the same way as the LEDs. Also drop the 1.2M Ohm resistor to 22K Ohms.
Incidentally, on the capacitor 'MPET' is probably the manufacturers name , '105' will be the value of 1uF and the '2E' is a manufacturer code, possibly for the maximum voltage it can withstand.
Brian.
Sorry Brian,.. I partly explained the reason in an earlier message...
Brian.
Hi Aaron,
No problem, everybody has it time to time...
Your plus 100 Ohm isnt a real problem, bigger importance has that your LED are not shurly with "only"1.5V to calculate!
Its to see on some concrete datasheet of your types or measure it on a battery/powersupply & some serial resistor that its current will be similar setted as in your application...
Technology & colour versions makes differences from so 1,5V up to more as 3V :-(
Greetings!
K.
Karesz is correct, different LED types have different voltage drops but the overall effect on brightness will be quite small. Be sure that the 22K resistor is rated at 2W or more and expect it to get quite hot!
Remember to keep your fingers out as well, those voltages bite hard!
Brian.
A word of caution, if you measure the voltage across the LEDs you will get a misleading result. The voltage is DC but the 1N400x diode is only letting current flow for half of each mains cycle so it isn't a steady voltage, it falls to zero and rises to a peak once per cycle. It means the LEDs will flicker but probably too fast to be noticeable. When you measure the voltage it will appear lower than you expect because for half the time the current is actually zero. There are ways to steady the voltage and to reduce the flicker but I suggest getting it working as it is for now. The extra components can be added to the existing circuit later.
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