visionbjp said:
--> which power is this talking about
"... However, the amplitude of the sine wave in the transient and PAC analyses can alternatively be specified as the power in dBm delivered by the port when terminated with the reference resistance. ..."
visionbjp said:
HOW is this voltage or current at the output of the port decided when you give ampiltude 1 (dBm) ??
\[
V_{internal, amplitude} = \sqrt{8*R * 10^{\frac{P_{dBm}}{10}-3}}
\]
\[
V_{out, amplitude} = V_{internal, amplitude}*\frac{RL}{R+RL}
\]
Examples:
Amplitude = -30 dBm
Resistance = 200 Ohm
V(internal, amplitude) = sqrt(8*200*10^(-30/10-3)) = 40 mV
1) RL = 100
V(out, amplitude) = (40 mV)*100/(100+200) = 13.3 mV
I(out, amplitude) = (13.3 mV)/(100 Ohm) = 133 uA
2) RL = 200
V(out, amplitude) = (40 mV)*200/(200+200) = 20 mV
I(out, amplitude) = (20 mV)/(200 Ohm) = 100 uA
3) RL = 300
V(out, amplitude) = (40 mV)*300/(300+200) = 24 mV
I(out, amplitude) = (24 mV)/(300 Ohm) = 80 uA