Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.
I simulate spiral inductor by HFSS.
inductance is normal , indudctance equation=im(Zin)/(2*pi*freq)
but Q-value is negative , Q equation= Q=im(Zin)/re(Zin)
Accoring to your equations, either re (Zin) must be negative (impossible for a passive circuit) or L would be negative, too. Apart from that, the Q equation would be valid only for a pure RL circuit, which is always in doubt for an inductor considering an extended frequency range.
Perhaps you should go back to the original definition of the quality factor: Q=1/tanδ.
The angle δ is simply the angle between voltage and current of the inductor (which is zero for a lossless inductor)
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.